Hi Pants! If my pex binary depends on a file target, in the code I put in this pex binary where should I look for the file? (e.g. the code needs to load a yaml file)

Hello! Hm you should have seen a warning when depending on

files()

that it is not included in the pex_binary. Did you see that? Also a warning at https://www.pantsbuild.org/docs/resources#files Instead, you would use

resources()

i added it as a dependency of the pex binary

Oh cool, so you are using

resources

. Great. The path should be equivalent to Python code, i.e. with the "source root" stripped. So if the resource is

src/py/project/foo.yaml

, then the resource would become

project/foo.yaml

. You load it with something like

importlib.resources.read_binary("project", "foo.ymal")

https://docs.python.org/3/library/importlib.html#module-importlib.resources

hmm, is there a way that would make it work with just

open("project/foo.yaml")

?

Using the link I sent you, it would be

importlib.resources.open_binary("project", "foo.yaml")

(or

open_text()

).

open()

won't work unfortunately

does "unzip" helps with it at all?

From the docs:

Filesystem APIs like Python's open() are relative to the current working directory, and they would try to read the files from where the binary is executed, rather than reading from the binary itself.

gotcha..

It might actually! I'm not sure, worth trying

yah i'm trying that now

would suggest unzipping the PEX (not that setting, literally unzipping), and looking at where the file is

@witty-crayon-22786 that's a good idea, thank you

so on the command line:

unzip -l ${myfile}.pex

execution_mode="unzip"

worked